Ideal Gas Calculator (moles from PV = nRT)
Enter pressure, volume and temperature of a gas to get the number of moles from the ideal gas equation.
Quick answer
1 atm, 22.4 L, 0 °C: 0.9994 mol.
How it is calculated
- Ideal gas equation: PV = nRT, so n = PV ÷ RT.
- R = 0.0821 L·atm/(mol·K); temperature in kelvin: T = °C + 273.15.
- n = 1 × 22.4 ÷ (0.0821 × 273.15) ≈ 1 mol.
Worked example
At 1 atm, 22.4 litres and 0 °C (273.15 K) the amount of gas is 0.9994 mol: the volume of 1 mole at STP.
| Pressure | 1 atm |
| Volume | 22.4 L |
| Temperature | 0 °C |
| Moles | 0.9994 mol |
Formula
PV = nRT
Moles = Pa×Vl/(0.082057×(Tc+273.15))
Good to know
- Always convert temperature to kelvin; entering °C directly gives a wrong answer.
- Real gases depart slightly from this equation at high pressure.
Questions people ask
What is R in PV = nRT?
0.0821 L·atm/(mol·K) or 8.314 J/(mol·K).
Volume of 1 mole at STP?
About 22.4 litres (0 °C, 1 atm).
Pressure in kPa?
1 atm = 101.325 kPa; convert to atm first.
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Updated 13 Nov 2026 · Desktop N Calculator v1.2.0